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Strings in general

Sudhanshu Mishra
Ranch Hand

Joined: May 28, 2011
Posts: 217

Hi all,
if i have a code like

String s1 = "spring ";
String s2 = s1 + "summer ";
s1.concat("fall ");
s2.concat(s1);
s1 += "winter ";
System.out.println(s1 + " " + s2);


and,I am asked how many objects are created,what should i answer.Actually this is an example from K&B book,and there the answer is eight,but what about the string
in the println method?even there we get a string.
Please correct me if i am wrong.I just want the answer i am expected to give in a SCJP 6.0 exam for this kind of question.
Please guide me through.
Thanks...
Rob Spoor
Sheriff

Joined: Oct 27, 2005
Posts: 19723
    
  20

I disagree with eight. I see ten:
1) "spring "
2) "summer "
3) "spring summer "
4) "fall "
5) "spring fall " - ignored but still created
6) "spring summer spring" - ignored but still created
7) "winter "
8) "spring winter "
9) " "
10) "spring spring summer "


The last two are probably missed in the count.


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Sudhanshu Mishra
Ranch Hand

Joined: May 28, 2011
Posts: 217

Thanks Rob,
But i am just concerned about my SCJP exam.If such a question is asked,what should i do.Should i skip the println statement and count just the objects in the code above println()?
Any suggestions would be helpful and much appreciated.
Rob Spoor
Sheriff

Joined: Oct 27, 2005
Posts: 19723
    
  20

I'll move this thread to our SCJP forum, where Bert Bates himself is hanging around. I'm sure he (or someone else) can give you a much better answer than I can.
Sam Hazim
Greenhorn

Joined: Jul 19, 2011
Posts: 26
I covered this chapter some weeks back, but if I recall correctly doesn't the question say something like 'there are eight objects created BEFORE the final System.out.println?'

There are 8 Objects at that point, and 10 Objects once the entire section runs.
Anjali Vaidya
Ranch Hand

Joined: Jan 25, 2011
Posts: 40

Hi Sudhanshu!



Eight objects before the println statement(that's the original question in book):
1.spring (stored in s1)
2.summer(lost)
3.spring summer(stored in s2)
4.fall(lost)
5.spring fall(due to result of s1.concat("fall") but not stored anywhere, so lost)
6.spring summer spring(due to result of s2.concat(s1) but not stored anywhere, so lost)
7.winter(lost)
8.spring winter(stored in s1. at this point, "spring" attached to s1 is lost)

so finally, only two are stored, all others are lost. Including println statement, there are 10 String objects
9." "
10.The entire println you are printing to screen i.e. spring winter spring summer
Sudhanshu Mishra
Ranch Hand

Joined: May 28, 2011
Posts: 217

Thanks a lot to everyone.
 
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subject: Strings in general