Beginning Spring: Syntax for Map<Integer, Double>?

[H Paul]

	private Map<Integer, Double> percentageLookup=new HashMap<Integer, Double>();
	
	public Pricer() {

		percentageLookup.put(100, 2d);
		percentageLookup.put(150, 2.5d);		
	}
	

Using Spring, is it possible to creat a Map<Integer, Double>? If so, what is the syntax? Any pointer.
so that I can percentageLookup = springContext.getBean("percentageLookup");

        <util:map id="percentageLookup" map-class="java.util.HashMap">
		        <entry key="100" value="2"/>
		        <entry key="150" value="2.5"/>
        </util:map>

With above config, the key is of type String, String.

percentageLookup.get("100") = 2
percentageLookup.get(100) = null

1M Thanks.

[N Sahni]

Hi,

You can try modifying your Map creation in spring as:
<util:map id="percentageLookup" map-class="java.util.HashMap" key-type="java.lang.Integer" value-type="java.lang.Double"> <entry key="120" value="1.5"/> <entry key="150" value="2.5"/> </util:map>

[H Paul]

1. Suggested code works.
2.

public class Pricer {
	public static final int DEFAULT_PCT = 2;

}

Some where we refer Pricer.DEFAULT_PCT.

Syntax-wsie: How can it be declared in Spring configuration file and refer to it?

[Mark Spritzler]

H Paul wrote:1. Suggested code works.
2.

public class Pricer {
	public static final int DEFAULT_PCT = 2;

}

Some where we refer Pricer.DEFAULT_PCT.

Syntax-wsie: How can it be declared in Spring configuration file and refer to it?

You can use the <util:constant> tag to use a constant value in your configuration.

Mark