Doubt related to var-args

[Divyya Joshi]

In case we try to define overloaded method that take wrapper class var-args as well as primitive type var-args , we can't not pass either single primitive or single wrapper at time of method call.. What does it mean?

Example

public class Flows{
          public static void main(String[] argv){
               callMethod(new Integer(2).intValue());
          }
          public static void callMethod(Integer... i){
               System.out.println("Wrapper");
          }
          public static void callMethod(int... i){
               System.out.println("Primtive");
          }
     }

what if i want to make this code error free without doing any change to both "public static void callMethod()" .

[Abhinav Shukla]

Compiler cant choose between primitive and boxed type if combined with varargs.

To be more general, 'varargs primitive', 'varargs + boxed primitive' and 'vargs + widened primitive' are consindered same; and are not legal for overloading.

Example : int.. , long... and Integer... are one and same and give error when used for overloading.