to print intege value of generic

[karthik swamy]

hello all'
i am using generics and here is the code:

public class generics {
public static <E> void printArray(E[] inputArray){
for(E element:inputArray){
Integer i=element/10; //error line
System.out.printf("%s ",i);
}
System.out.println();
}
public static void main(String ...args){
Integer[] array={10,20,30,40,50,60,70,80,90,100};
System.out.println("The array contains: ");
printArray(array);
System.out.println("hello world");

}
}

if i didnt use that error line that it gives the desired output
but if i use that line it gives error that : The operator / is undefined for the argument type(s) E, int

and i need to display 1 2 3 4 5 6 7 8 9 10

so please tell me where i a wrong..

thanks
karthik swamy.

[massimiliano cattaneo]

Try this
You are using a generics so the / operator is not defined.

public static <E extends Number> void printArray(E[] inputArray){
     for(E element:inputArray){
             Integer i=element.intValue()/10; //error line
             System.out.printf("%s ",i);
     }
     System.out.println();
   }

   public static void main(String ...args){
     Number[] array={10,20,30,40,50,60,70,80,90,100};
     System.out.println("The array contains: ");
     printArray(array);
     System.out.println("hello world");
   }

[karthik swamy]

massimiliano cattaneo wrote:Try this
You are using a generics so the / operator is not defined.

public static <E extends Number> void printArray(E[] inputArray){
     for(E element:inputArray){
             Integer i=element.intValue()/10; //error line
             System.out.printf("%s ",i);
     }
     System.out.println();
   }

   public static void main(String ...args){
     Number[] array={10,20,30,40,50,60,70,80,90,100};
     System.out.println("The array contains: ");
     printArray(array);
     System.out.println("hello world");
   }

Thanks it works fine.