JPA Newbie Question

[Frank Jones]

Hi, I'm trying to set up my first JPA app, and while I'm able to get it to work outside a J2EE container, or within a J2EE container using the following code:

		EntityManagerFactory emf = Persistence.createEntityManagerFactory("Test_JPA");
		EntityManager em = emf.createEntityManager();

		FrankObject frank = new FrankObject();
		frank.setFrankId(13);
		frank.setFrankValue("frank");
				
		em.persist(frank);
		
		em.close();
		emf.close();

I'm unable to get it to work using the @PersistenceContext annotation. My understanding was that the two below things would both successfully load the EntityManager in the same 'em' reference:

1..

		EntityManagerFactory emf = Persistence.createEntityManagerFactory("Test_JPA");
		EntityManager em = emf.createEntityManager();

2..

	@PersistenceContext(name="Test_JPA")
	EntityManager em;

But when I run option 2, I get this error:

org.apache.jasper.el.JspELException: /login.jsp(28,2) '#{loginBean.processLogin}' javax.ejb.EJBException: java.lang.IllegalArgumentException: Unknown entity: frank.jpa.FrankObject

Caused by:
java.lang.IllegalArgumentException - Unknown entity: frank.jpa.FrankObject

I'm sure there's something dumb I'm missing, but if anyone could tell me what it is, I'd be grateful

ps. I am using JBoss 6 and MySQL, if that is relevant.

[Frank Jones]

Ok I've fixed it, I'll post up what I did in case it saves somebody else the headache I've had trying to get this to work

I think there was two things I did wrong, first I think I was supposed to set 'unitName' on the persistence context, not 'name':

@PersistenceContext(unitName="Test_JPA")

Secondly I packaged the application wrong, I had an ear file, with a WAR, an EJB JAR, a plain JAR and a persistence unit JAR, all in the root. I changed it so that only the WAR and EJB JAR were in the root, and the plain JAR and persistence unit JAR were in the lib subdirectory of the EAR.