This week's book giveaway is in the OO, Patterns, UML and Refactoring forum.
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Be The JVM (Head First)

Tariq Ab

Joined: Oct 24, 2009
Posts: 14
I don't understand how we got the output?!!
What's the first output in line 14? how do we calculate what's the value coming out of the loop? line 12?!

Answer is 13 15 x = 6
John Jai

Joined: May 31, 2011
Posts: 1776
In line #11 - you increment the value of y for every iteration in the for loop.

In line #12 - you check whether value of x is greater than 4. If so you increment the value of y.

In line #16 - you check whether value of y is greater than 14, If so then you use the break command to exit the for loop. Once a break is executed the for loop is terminated and the value of y will be 15 outside the for loop..

Try to run below program to understand it. If you work out with a pencil and paper you will understand it better.

Tariq Ab

Joined: Oct 24, 2009
Posts: 14
Thank you so much Sir,

Finally got it. had to read it a couple of times letter by letter.

Now i can go to bed
Have you checked out Aspose?
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