could not deserialize the context attribute

[Satyajeet Kadam]

i get following exception while running

Q1) how to deserialize context attribue?



(id=16715083,name=kala,context-path=/kala)] could not deserialize the context attribute "org.apache.struts.action.REQUEST_PROCESSOR"
java.io.NotSerializableException: org.apache.struts.action.RequestProcessor

    
package demo; 
 
import java.io.*;
 

 
import java.util.*; 
 
import javax.servlet.*; 
 
import javax.servlet.http.*; 
 
import org.apache.struts.action.*; 
 

import java.security.*;
public class kalaAction extends Action
{ 
 
public ActionForward execute(ActionMapping mapping, 
 
ActionForm form, 
 
HttpServletRequest request, 
 
HttpServletResponse response) 
 
throws IOException, ServletException 
 
{ 
 
kalaForm kalaform =(kalaForm) form; 
 
String a = kalaform.getState(); 
 
if(a.equals("TAMILNADU") || a.equals("KERALA") || a.equals("KARNATAKA")) 
 
{ 
 
kalahelper helper = new kalahelper(); 
 
String r = helper.callejb(a); 
 
kalaresult kr = new kalaresult(); 
 
kr.setValue(r); 
 
String m = kr.getValue(); 
 
System.out.println("From Action "+m); 
 
HttpSession session= request.getSession(); 
 
session.setAttribute("result",kr); 
System.out.println("session =="+ session.getAttribute("result"));
 
return mapping.findForward("success"); 
 
} 
 
else 
 
{ 
 
ActionErrors errors = new ActionErrors(); 
 
errors.add (ActionErrors.GLOBAL_ERROR, new ActionError("errors.wrongname")); 
 
saveErrors(request,errors); 
 
return(mapping.findForward("failure")); 
 
} 
 
} 
 
}