Returning a byte-array after performing an XSLT

[Martin Fiskare]

Hej!

Me again with another nerve-wrecking issue, since I'm not very experienced witj java and xml

What i need to do is marshal Dummy.class and return the result in form of a byte array. Problem is I can't do that straight like marshalling directly into a ByteOutputStream, because I have to modify the output by performing an XSLT.

In other words, what I want to do is
- Marshal my class structure to whatever result might be necessary
- transform the result
- return the result in form of a byte-array.

That's what I have right now..

ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
byte[] returnValue;
Source xsltSource = new StreamSource(getClass().getClassLoader().getResourceAsStream("doSomething.xsl"));

TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer(xsltSource);

Dummy dummy = fillDummy();
jc = JAXBContext.newInstance(Dummy.class);
Marshaller m = jc.createMarshaller();
m.marshal(timetable, outputStream);
//annoying lack of ideas...
return outputStream.toByteArray();

Thanks thousandfold in advance for any help

[Karthik Shiraly]

Use javax.xml.bind.util.JAXBSource

[Martin Fiskare]

Ok, that looks useful at the first glance.. but, when does the actual marshalling happen?
Does is happen implicitly when I instantiate the JAXBSource?

And besides.. the result of the transformation has somehow to be a byte-array.. and i have no clue how I can achieve that.

[Karthik Shiraly]

Both marshalling and transformation happen when the transform() is called. JAXBSource is just an adaptor between JAXB and transformer - it calls marshal() as soon as the transformer asks it for an XML input stream.

As for the byte array, well you're already half way there:

// create JAXBSource and transformer

ByteArrayOutputStream outputStream = new ByteArrayOutputStream();  
StreamResult result = new StreamResult(outputStream);
transformer.transform (jaxbSource, result);
resultArray = outputStream.toByteArray();
return resultArray;

[Karthik Shiraly]

Just occurred to me now...why do you need a byte array as output? Perhaps there is a better way, if you can explain the circumstances.