I am new here.
I could not able to run my first script. I am using Windows XP.
First I have installed Apache server httpd-2.2.21-win32-x86-no_ssl.msi . I also installed PHP php-5.3.8-nts-Win32-VC9-x86.msi .
On the Apache Service Monitor I can Start, Stop server.
On the command prompt I got the details such as PHP version, built date,time etc. by executing php -v command.
On the browser I got "It works!" when I typed address http://localhost/ I placed phpinfo.php file in "C:\Program Files\Apache Software Foundation\Apache2.2\htdocs".
My problem is I am getting output code of my PHP file phpinfo.php
The contains of file phpinfo.php
I am getting output as
Please help me!
Thanks in Advance.
Oracle Certified Professional, Java SE 6 Programmer.
Joined: Apr 04, 2009
Not so simple, unfortunately.
The problem is that apache needs to be told that if a .php is requested, send it to the PHP interpreter. The way to do it is to have a line like "LoadModule php5_module "/your_php_installation_path/php5apache2.dll" in httpd.conf and configure it as a MIME module. Search for tutorials on net if you want to get into that stuff.
However, if you just want to start with PHP as quickly as possibly, then you're better off installing a preconfigured Apache + PHP + mysql stack like XAMPP or WAMP -it'll have everything already configured.