XSL: cycle every element

[Marco Rossi]

Hi all,

I need to verify if any element of an XML file contains an attribute called "id"; for example:

<person> <name> Bob </name> <city id="5"> London </city> </person>

And this is what I wrote but it seems not working

<xsl:for-each select="$xmlFile/node()" > <xsl:variable name="currentNode" select="current()"/> <xsl:choose> <xsl:when test="$currentNode/@id"> <xsl:message>ID ok for element <xsl:value-of select="$currentNode" /> </xsl:message> </xsl:when> <xsl:otherwise> <xsl:message>No ID for element <xsl:value-of select="$currentNode" /> </xsl:message> </xsl:otherwise> </xsl:choose> </xsl:for-each>

When I print $currentNode I would like to get printed the name of the node.

Thanks
Marco

[Paul Clapham]

I don't know what that "$xmlfile" variable might be, but you are only looking at its children in that code, not all of its descendants.

Why don't you just write an XPath expression which selects all nodes with an "id" attribute? That would be far easier than writing your own code to search the document.

[g tsuji]

@Marco Rossi
Instead of this:
>select="$currentNode"
do this

select="name($currentNode)"