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# Iteration using Newton Raphson's method

John Morris
Greenhorn

Joined: Nov 25, 2011
Posts: 4

This is the assignment >>----http://www.cs.fiu.edu/~smithjo/assignments_2xxx/assign2xxx5_a.docx

*****************

Here is my code

I tried to put some kind of equation but it loops infinitely...

Help please. It's due sunday, at least a pointer. a hint...anything >.<

HOLY COW CodeBatman!!
Tim Moores
Rancher

Joined: Sep 21, 2011
Posts: 2408
x starts out at 5.

The while loop checks whether x is larger than 0.005 (note that "x * (n + 1) - x * n" is identical to "x").

The value of x never changes.
John Morris
Greenhorn

Joined: Nov 25, 2011
Posts: 4

But that doesn't show me how to form the equation. I'm still completely lost :/

I have to make it stop when it's equal to 0.005

and output all iterations.
Tim Moores
Rancher

Joined: Sep 21, 2011
Posts: 2408
John Morris wrote:But that doesn't show me how to form the equation.

You asked for a hint, you got a hint. It's your homework - hints is all you'll get.

You will need two variables for x, let's say x0 and x1. x0 would be the value calculated in the previous iteration, and x1 the value calculated in the current iteration. You want the loop to stop when abs(x0-x1) < 0.005.
Campbell Ritchie
Sheriff

Joined: Oct 13, 2005
Posts: 34513

13
Welcome to the Ranch

We won’t show you how to form the equation, but will give hints or helps if you show an example with errors. You should write the algorithm on paper, then you can see what you have got to code.
Mohamed Sanaulla
Bartender

Joined: Sep 08, 2007
Posts: 3010

27

... And as a tip- please UseCodeTags when you are posting some code. This time I have done it for you and see how good it looks

Mohamed Sanaulla | My Blog

With a little knowledge, a cast iron skillet is non-stick and lasts a lifetime.

subject: Iteration using Newton Raphson's method