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Scanner debugging help

Haani Naz

Joined: May 30, 2010
Posts: 23
Hi there,

I have the following piece of code which fails at the point it needs to accept input and i can't seem to figure out why.

The issue is at line 115.

Here is the output:

As you can see instead accepting input it skips it.

can somebody please tell me why?

thanks in advance!
Anniruddh Rana

Joined: Nov 30, 2011
Posts: 18

Change that to

and give it a try.

i.e. use System.out.print there instead of System.out.println
jQuery in Action, 3rd edition
subject: Scanner debugging help
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