Resolve current directory in xsl file

[Sankar Mitra]

I want to access the java function of a class that resides in a jar which in turn is converted into a dll file. I there any way to get the current directory in xsl file.

<xsl:transform version="1.0" xmlns:t1package.Parse" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

[Paul Clapham]

Probably not. But why would you need to know the current working directory for that?

[Sankar Mitra]

Actually the dll file containing the java files and the xsl files resides in the same directory.So I am just thinking that if I can get the current directory in Xsl then it will be easy to access functions from java files.I will ahve to rewrite it as

<xsl:transform version="1.0" xmlns:t1="currentDirectory/cts.Parse" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >

[Paul Clapham]

How do you plan to call the DLL functions directly from the XSL?