Another question about Array

[Wu Wen]

class Test
{
   public static int[ ] getArray() {  return null;  }
   public static void main(String[] args)
   {
      int index = 1;
      try
      {
         getArray()[index=2]++; //1
      }
      catch (Exception e){  }  //empty catch
      System.out.println("index = " + index);
   }
}

Why it prints out index = 2 instead of throwing an exception at //1 ?

[Nitin Surana]

It throws an exception, but you have already caught that.

Wu Wen wrote:

      catch (Exception e){  }  //empty catch

[Javin Paul]

why are you coding like that, what do you want to test ?

[O. Ziggy]

What exactly does this line do..

getArray()[index=2]++; //1  

[Abdullah Mamun]

1. method getArray() is called.
2. index variable set with value 2.
3. trying to fetch the value of 2nd index of the array that returned by getArray() method which is null and exception occurs.

[O. Ziggy]

Thanks