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Classpath in Command line

Nelo Angelo
Ranch Hand

Joined: Jul 25, 2011
Posts: 44

Hello everyone,

I was going through Head First Servlets book and found myself stuck in the BeerSelect.java example.

=======
PROBLEM
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To compile the servlet following code is being used:
% javac -classpath /Users/bert/Applications2/tomcat/common/lib/servlet-api.jar:classes:. -d classes src/com/example/web/BeerSelect.java

I am using Windows XP and my Tomcat directory's path is this:
C:/Program Files/Apache Software Foundation/Tomcat 5.5/common/lib;


So I am using this code in the command prompt to compile, but it generates an error:
C:\beerV1>javac -classpath /Program Files/Apache Software Foundation/Tomcat 5.5/common/lib//servlet-api.jar:classes:. -d classes src/com/example/web/BeerSelect.java

Error:
javac: invalid flag: Files/Apache
Usage: javac <options> <source files>


I love java but she hates me... :'(
arvind kushwaha
Ranch Hand

Joined: Aug 12, 2011
Posts: 32
set the classpath for your program. For eg.

c:> set classpath=.;Here provide the path of your servlet-api-jar; %z%;
Nelo Angelo
Ranch Hand

Joined: Jul 25, 2011
Posts: 44

Thanks for the replies, but I want to know how the above given code can be modified to be used in Windows. The compound statement that sets the classpath as well as compiles the code.
Campbell Ritchie
Sheriff

Joined: Oct 13, 2005
Posts: 37986
    
  22
You would appear to have misread the previous post, which uses a Windows® idiom.
Yoiur question is not at all clear. Do you mean this
javac -cp .;c:\MyFolder\MyOtherFolder\MyJar.jar MyClass.java
Shankh Pani Parimal
Greenhorn

Joined: Dec 29, 2011
Posts: 8



shankh
Nelo Angelo
Ranch Hand

Joined: Jul 25, 2011
Posts: 44

Thanks for the reply guys, the problem is resolved.

I used the following code:

C:\beerV1>javac -cp C:\Tomcat_6.0\lib\servlet-api.jar; -d classes src/com/example/web/BeerSelect.java
 
Don't get me started about those stupid light bulbs.
 
subject: Classpath in Command line
 
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