reference id

[abhinav sood]

this program gives the output null and zero can any one explain that.....

class emp {
  String name;
  int salary;

  void get(String s1,int s2) {
    name=s1;
    salary=s2;
  }

  void show(){
    System.out.println(name);
    System.out.println(salary);
  }

  public static void main(String... s) {
    new emp().get("abhinav ",123);
    new emp().show();
  }
}

[moderator edit: added code tags]

[Jan Cumps]

Welcome to the Ranch, Abhinav !

can any one explain that.....

yes:

First you call:

new emp().get("abhinav ",123);   

This will create a new emp() object, call its get() member, and then loses the reference to the object (you don't store the object in a variable).

Then you call:

new emp().show();   

This will create a brand new object, call its show() method -- that will print null and 0 because you didn't use get() to set its members, and then loses the reference to the object too.



What should you have done:

when creating the object, store it in a variable of type emp (emp myEmp = new ....)
then call the members of that variable (myEmp.get(), myEmp.show() )



Some style remarks:
A class by convention starts with upper case (class Emp)
A method to set properties should be called set..(), not get..().