Using recursion to print alternating squares?

[Bear Kim]

Hi, I'm trying to use recursion (no loops) to print out descending odd, then ascending even squares less than a certain number.
For examples, squares(5) would print out: 25, 9, 1, 4, 16.
I'm not sure how I would alternate between even/odd, and would really appreciate some help with that.

Right now, I have it so that all squares are printed in descending order. All input is greatly appreciated!

public static void squares(int n)
{
	if (n < 1)
	{
		throw new IllegalArgumentException();
	} else
	{
		System.out.print(n*n);
		squares(n-1);
	}
}

[Seetharaman Venkatasamy]

You are almost done.
One Suggestion: why do you throw Exception from base condition, I do suggest you to just return.

Hint : even number * even number => even number ; odd number * odd number => odd number.
So, when you encounter even number dont print it instead put into a *X* datastructure. and print it later in base condition before return.

[Darryl Burke]

Bear, please BeForthrightWhenCrossPostingToOtherSites
http://www.java-forums.org/new-java/56462-using-recursion-print-alternating-squares.html

Any more?

[Seetharaman Venkatasamy]

Good Kim, you wasted my time!

[Bear Kim]

Sorry, I'm confused, why is cross-posting bad? Thanks for the help anyways though, other site wasn't much help.

[Seetharaman Venkatasamy]

Bear Kim wrote:why is cross-posting bad?

refer Darryl's Post.