Astha Sharma wrote:Why doesn't it throw ArithmaticException?

Instead it prints infinity. Isn't java partial with int in this case

Not sure what you mean by "partial with int", but Java supports the IEEE 754 floating point standard -- and that's how it is defined. A positive number divided by positive zero results in positive infinity.

But Arithmatic Exception is thrown when this is written-
int i=100/0;
Shouldn't the exception also be thrown when we devide a double with 0?
double i=100.0/0

Astha Sharma wrote:But Arithmatic Exception is thrown when this is written-
int i=100/0;
Shouldn't the exception also be thrown when we devide a double with 0?
double i=100.0/0

Well, as Henry Wong has already mentioned, 'double' in Java follows IEEE 754 floating point standard. As per that, a positive floating point number devided by 0 results in positive infinity.

'int' in Java does not follow this standard, and hence we get ArithmeticException.

Astha Sharma wrote:But Arithmatic Exception is thrown when this is written-
int i=100/0;
Shouldn't the exception also be thrown when we devide a double with 0?
double i=100.0/0

For ints, Java follows the two complement format -- and that format doesn't define infinity. Hence, it throws an exception. For floats, as mentioned, it follows the IEEE format.

Also, note that these two are the common format that are supported by most (if not all) modern day processors and languages.

Perhaps, you are asking why the standards don't agree? (which of course, we can only speculate) Henry