This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
I am running Tomcat 5.5.4 and have a servlet running with no problems. However, I'd like to set up a mapping to only launch the servlet when a URL containing a particular query string is submitted.
Right now in web.xml I have:
If a browser submits http://localhost/MyServer/go?P=123 the servlet is launched and all is well. However, I'd like to only launch that servlet if the URL is exactly as just shown. Unfortunately, right now if the URL is http://localhost/MyServer/go?P=AnyDarnThing the servlet still launches. I have tried setting up the following:
but this results in The requested resource (/MyServer/go) is not available.
I've tried numerous variations (quoting the string, ...) on the above URL pattern but I always get the above error. I notice that if I (for debugging purposes) drop the "?" as in
I no longer get the error message and the server launches (but, of course, it doesn't respond to the "query string" because it's not properly formed.) This suggest to me that the "?" is causing a problem in the mapping. I've tried replacing it with its URL special character equivalent as follows:
but this gives the same result just described above when I tried dropping the "?" altogether.
I realize I can let the servlet get launched when any query string is submitted and then "ignore" the request for all but the one I care about but there is a reason I'd prefer to not have the servlet launched to begin with. So, my question is, how can I configure the servlet so that it is only launched when a specific query string is included?