# weird IQ question

Myke Enriq

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Joanne Neal

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Posts: 3742

16

Ryan McGuire

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Posts: 1055

4

posted 4 years ago

This reasoning might be non sense . even though would like to give a try :

here is my Observation :

Lets consider 1 to 10*

Ralphs like:

25 => 2+5 = 7 odd number

144 => 1+4+4 = 9 odd number

300 => 3+0+0 = 3 odd number

Ralph's dislike:

24 => 2+4 = 6 even

145 = > 1+4+5 = 10 even

400 => 4+0+0 = 4 even

Options:

37 => 3+7 = 10 even

64 => 6+4 = 10 even

200 => 2+0+0 = 2 even

1024 => 1+0+2+4 = 7 odd

65535 => 6+5+5+3+5 => 11+8+5 => 19+5 => 2+4 => 6 even

So my guess would be 1024 .

here is my Observation :

Lets consider 1 to 10*

Ralphs like:

25 => 2+5 = 7 odd number

144 => 1+4+4 = 9 odd number

300 => 3+0+0 = 3 odd number

Ralph's dislike:

24 => 2+4 = 6 even

145 = > 1+4+5 = 10 even

400 => 4+0+0 = 4 even

Options:

37 => 3+7 = 10 even

64 => 6+4 = 10 even

200 => 2+0+0 = 2 even

1024 => 1+0+2+4 = 7 odd

65535 => 6+5+5+3+5 => 11+8+5 => 19+5 => 2+4 => 6 even

So my guess would be 1024 .

Ryan McGuire

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posted 4 years ago

Given the information presented so far, that seems like a perfectly reasonable explanation, Seetharaman. You even came up with the correct answer (where "correct" is defined as "what I was thinking"), but for a different reason.

We already know that 25, 144, 300 and 1024 are "likable" but 24, 145, 400, 37, 64, 200 and 65535 are "unlikable". However, I'm going to declare that 8889 is likable while 97 unlikable. How can that possibly be?

We already know that 25, 144, 300 and 1024 are "likable" but 24, 145, 400, 37, 64, 200 and 65535 are "unlikable". However, I'm going to declare that 8889 is likable while 97 unlikable. How can that possibly be?

Anubrato Roy

Greenhorn

Posts: 3

posted 3 years ago

My take is that Ryan likes numbers where the

Here is my logic -

Ryan's likes:

25 => 5 – 2 = 3

144 => (1+4) – 4 = 1

300 => (3+0) – 0 = 3

Ryan's dislikes:

24 => 4 – 2 = 2

145 => (1+5) – 4 = 2

400 => (4+0) – 0 = 4

Also, as already declared,

8889 => (8+9) – (8+8) = 1

97 => 9 -7 = 2

So given all the above, the available options are:

37 => 7 – 3 = 4

64 => 6 – 4 = 2

200 => (2+0) – 0 = 2

1024 => (4+0) – (1+2) = 1

65535 => (6+5+5) – (3+5) = 8

That leaves 1024 as the only option

*difference of sum of the alternate digits is*.**odd**Here is my logic -

Ryan's likes:

25 => 5 – 2 = 3

**Odd**144 => (1+4) – 4 = 1

**Odd**300 => (3+0) – 0 = 3

**Odd**Ryan's dislikes:

24 => 4 – 2 = 2

**Even**145 => (1+5) – 4 = 2

**Even**400 => (4+0) – 0 = 4

**Even**Also, as already declared,

8889 => (8+9) – (8+8) = 1

**Odd**97 => 9 -7 = 2

**Even**So given all the above, the available options are:

37 => 7 – 3 = 4

**Even**64 => 6 – 4 = 2

**Even**200 => (2+0) – 0 = 2

**Even**1024 => (4+0) – (1+2) = 1

**Odd**65535 => (6+5+5) – (3+5) = 8

**Even**That leaves 1024 as the only option

Ryan McGuire

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4

posted 3 years ago

I would say that qualifies as "humorously correct". Yes, I do indeed like 1024. Also, the rule you stated will correctly identify numbers I like versus the ones I don't like. However, the statement of the rule is more complicated than the one I had in mind.

If we know that the difference between two numbers is either even or odd, what can we say about the sum of those same numbers?

If two numbers have an even sum, how even numbers did we start with? How many odd?

(Addition is associative and commutative.)

Is there a simpler rule that is equivalent to the "odd difference of sums of alternate digits" one given above?

Anubrato Roy wrote:My take is that Ryan likes numbers where thedifference of sum of the alternate digits is.odd

I would say that qualifies as "humorously correct". Yes, I do indeed like 1024. Also, the rule you stated will correctly identify numbers I like versus the ones I don't like. However, the statement of the rule is more complicated than the one I had in mind.

If we know that the difference between two numbers is either even or odd, what can we say about the sum of those same numbers?

If two numbers have an even sum, how even numbers did we start with? How many odd?

(Addition is associative and commutative.)

Is there a simpler rule that is equivalent to the "odd difference of sums of alternate digits" one given above?

Anubrato Roy

Greenhorn

Posts: 3

posted 3 years ago

Hi Ryan,

It was amusing to realize that I have stated the rule in a complicated manner.

Taking your hint, if the difference of 2 numbers is odd, then one of them is even and the other odd - which implies that their sum is also odd.

That combined with my logic simply means that the sum of all the digits in the number must be odd.

So here is the revised version -

You like numbers where the

That makes me realize that this is almost identical to Seetharaman's logic, except that I stop only at the first pass of summing up the digits; and not summing up the digits of the sum itself.

Regards,

Anubrato

It was amusing to realize that I have stated the rule in a complicated manner.

Taking your hint, if the difference of 2 numbers is odd, then one of them is even and the other odd - which implies that their sum is also odd.

That combined with my logic simply means that the sum of all the digits in the number must be odd.

So here is the revised version -

You like numbers where the

*sum of digits of the numbers is*.**Odd**That makes me realize that this is almost identical to Seetharaman's logic, except that I stop only at the first pass of summing up the digits; and not summing up the digits of the sum itself.

Regards,

Anubrato

Ryan McGuire

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Posts: 1055

4

posted 3 years ago

As it turns out, that's correct as well as now being relatively succinct. What I really like about the "likable" numbers is that they have an odd number of odd digits. ...which turns out to be equivalent to liking numbers where the sum of digits is odd.

Anubrato Roy wrote:

So here is the revised version -

You like numbers where thesum of digits of the numbers is.Odd

As it turns out, that's correct as well as now being relatively succinct. What I really like about the "likable" numbers is that they have an odd number of odd digits. ...which turns out to be equivalent to liking numbers where the sum of digits is odd.