not able to understand the output of the following piece of code ?

[gurpeet singh]

static int i[];
    public static void main(String... args)
    {
        int eye[] = new int[6];
        try
        {
            try{
                System.out.println(i.length);
            }
            finally{
                i = eye;
            }
        }
        catch (RuntimeException e)
        {
            e.printStackTrace();
            System.err.println(i.length);
        }
    }
}

when i ran this code it gives me null pointer exception followed by 0. i know that i points to null and when we did System.out.println(i.length) it gives runtime exception . but according to me since the nested try block does not have any associated catch block , so when an exception is throw in it , the control will go inside finally block , which assigns reference of eye to i . but i know that catch block runs which prints the output . i want to know is that how come catch block gets executed since inner try block does not have any associated catch block with it. please explain

[John Jai]

The flow would be Inner try block -> Inner finally block -> Outer catch block for any Exception should occur and no catch block is present for the inner try block.

[dennis deems]

The presence of the finally block doesn't stop the exception from propagating out to the enclosing try/catch. It just means that before that happens, the code inside the finally block will execute. If the inner try block were accompanied by a catch, then the exception wouldn't propagate outwards.

[Seetharaman Venkatasamy]

John Jai wrote:The flow would be Inner try block -> Inner finally block -> Outer catch block for

unless there is an exception immediately after the Outer try else, inner finally block will be skipped

[John Jai]

Seetharaman Venkatasamy wrote:

John Jai wrote:The flow would be Inner try block -> Inner finally block -> Outer catch block for

unless there is an exception immediately after the Outer try else, inner finally block will be skipped

Yes - when the inner try din't even get executed.