The requested resource (/Person/) is not available.

[Omar Perez]

Greetings,

Well I'm stuck in a example of the book Head First Servler and JSP, however I don't see why the code is not working as it should. It should display "Person is : Evans"

The Javabean

package foo;

public class Person {
	
	private String name;
	
	public String getName(){
		return name;
	}
	
	public void setName(String name){
		this.name=name;
	}
	


}

The Servlet

package servlet;

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;


public class WebServlet extends HttpServlet {
	
	public void doPost(HttpServletRequest request, HttpServletResponse response)
	throws IOException, ServletException {
		
		foo.Person p = new foo.Person();
		p.setName("Evan");
		request.setAttribute("person", p);
		
		RequestDispatcher view = request.getRequestDispatcher("result.jsp");
		view.forward(request, response);
	}

}

DD

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/javaee" 
	     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	     xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
	     version="3.0">
	     
	     
	     <servlet>
	     <servlet-name>WebServlet</servlet-name>
	     <servlet-class>WebServlet</servlet-class>
	     </servlet>
	     
	     <servlet-mapping>
	     <servlet-name>WebServlet</servlet-name>
	     <url-pattern>/servlet.do</url-pattern>
	     </servlet-mapping>
	     
	     </web-app>

[Koen Aerts]

You servlet class (web.xml) should be "servlet.WebServlet" not "WebServlet". You have to specify the whole class name, that includes the package.

[Bear Bibeault]

And, you went through all the trouble to create servlet mapping for the servlet. Why aren't you using it?

[Omar Perez]

Koen Aerts wrote:You servlet class (web.xml) should be "servlet.WebServlet" not "WebServlet". You have to specify the whole class name, that includes the package.

I get the same error, with or without the full qualified name.

[Omar Perez]

Bear Bibeault wrote:And, you went through all the trouble to create servlet mapping for the servlet. Why aren't you using it?

It just doesn't work at all, I get the same error.

[Rob Spoor]

You're trying to access /Person/ but you only have a servlet mapping for /servlet.do. I'm also not seeing any filters or other servlet mappings, so what makes you think there even is a /Person/ resource?

[Omar Perez]

Rob Spoor wrote:You're trying to access /Person/ but you only have a servlet mapping for /servlet.do. I'm also not seeing any filters or other servlet mappings, so what makes you think there even is a /Person/ resource?

Servlet.do is a logical name, nothing else. I'm using eclipse and the name of the project is eclipse, so it should upload the app as the project's name "Person".

[Piyush Mangal]

Person would be your web application context name and as you do not have any index.html or index.jsp etc, you need to provide the logical name as well in your url. It should be something like http://localhost:8080/Person/servlet.do assuming your web server is running on 8080 on your local machine.

[Bear Bibeault]

Omar Perez wrote:

Rob Spoor wrote:You're trying to access /Person/ but you only have a servlet mapping for /servlet.do. I'm also not seeing any filters or other servlet mappings, so what makes you think there even is a /Person/ resource?

Servlet.do is a logical name, nothing else. I'm using eclipse and the name of the project is eclipse, so it should upload the app as the project's name "Person".

That makes no sense at all. If the name of the project is "eclipse" what does that have to do with "Person"? And once again, you access servlets through the servlet mappings.