fetch in integer variable

[Megha Singhal]

how to fetch following string array into integer array

String cn[]=request.getParameterValues("ccno");

i am doing like following

int cno[]=Integer.parseInt(cn);
			if(cno!=null) {
			for (int i=0;i<cno.length;i++){
			out.println(cno[i]);

but it is giving compile time error.

[Punit Jain]

try this:

public class Test {
	public Test() {
		// TODO Auto-generated constructor stub
	String arr[]={"1","2","3"};
	for(int i =0;i<arr.length;i++){
		if(arr[i]!=null){
		int ab = Integer.parseInt(arr[i]);
		System.out.print(ab);
		}
	}
	}
	public static void main(String args[]){
		new Test();
	}
}

[Matthew Brown]

Integer.parseInt takes a String as the argument, but you're passing it a String array.

To convert an array of Strings into an array of ints, you need to create the int array of the right size, then loop round the arrays converting each individual String to an int.

[Athira Vineeth]

Hi,

Try this

int cno[] = new int[cn.length];
for (int i = 0; i < cn.length; i++) {
	cno[i] = Integer.parseInt(cn[i]);
}