How to move a video file(*.flv) from a directory to another directory

[Subrata Pradhan]

I am facing a problem for few days to move a video file from a client machine directory to a specific directory in server . I am using multipart/form-data for choosing multiple video files(*.flv) and commons-fileupload.jar and commons-io.jar for uploading purpose.

My Jsp File:

<form enctype="multipart/form-data" id="fileupload" method="post" action="">
<table>
	<tr>
		<td>Choose File 1</td><td>:</td><td><input type="file" id="path1" name="path1"></td>
	</tr>
	<tr>
		<td>Choose File 2</td><td>:</td><td><input type="file" id="path2" name="path2"></td>
	</tr>
</table>
<table><tr><td><input type="submit"></td></tr></table>
</form>

JAVA CODE:

	boolean isMultipart = ServletFileUpload.isMultipartContent(request);
    InputStream uploadedStream=null;
	try
	{
		if(isMultipart) 
		{	
			FileItemFactory factory = new DiskFileItemFactory();
			ServletFileUpload upload = new ServletFileUpload(factory);
			List items = null;
			String name = null;
			String value = null;
			String filenames = null;
			try 
			{
				items = upload.parseRequest(request);
			} 
			catch (FileUploadException e) 
			{
				e.printStackTrace();
			}
			Iterator itr = items.iterator();
			while (itr.hasNext()) 
			{
				DiskFileItem   item = (DiskFileItem) itr.next();
				if (!(item.isFormField()))
				{
					name = item.getFieldName();
					uploadedStream  = item.getInputStream();
					if(item.getSize()!=0)
					{  
						System.out.println("the file path>>>"+item.getOutputStream());
					}
				}
			}		
		}
	}
	catch(Exception e){}	

[Rob Spoor]

Welcome to the Ranch!

OK, so you already are able to get an InputStream for the uploaded file. What you now need to do is create a FileOutputStream, and copy all contents from the InputStream to that FileOutputStream. Make sure to close both streams when you're done with it, in a finally block.

[Bear Bibeault]

What is this doing in your code?

Subrata Pradhan wrote:
catch(Exception e){}

[Rob Spoor]

Bear is right. You should never ever catch exceptions and ignore them. If they occur you won't be informed in any way. The very least you should do is log it, by calling e.printStackTrace().

[Subrata Pradhan]

Rob Spoor :
OK, so you already are able to get an InputStream for the uploaded file. What you now need to do is create a FileOutputStream, and copy all contents from the InputStream to that FileOutputStream. Make sure to close both streams when you're done with it, in a finally block.

Thanks Rob...thanks for the help :)