unreachible code detected

[Branden Bobo]

Can anybody tell me why the compiler tells me unreachible code detected in line: 12

I'm guessing it's detecting the inner loop as an infinite loop, but I can't figure out the logical error?

public long getNextPrime()
 {
   currentPosition++;
    boolean isPrime = true;
  for(long testNum = currentPrime;;testNum++)
  {
    
    for(int i=2, limit = (int)Math.sqrt(testNum)+1;;i++)
    {
      isPrime = testNum % i != 0;
    }
    if(isPrime)
    {
      return testNum;
    }
  }
 }

[Paul Clapham]

If I read that for-loop right, then it doesn't have a termination condition. So yes, I suppose the compiler might well observe that and classify it as an infinite loop.

[Branden Bobo]

Thanks, I feel stupid, I've been staring at this method for 30min stumped by somethiing I should have know(seen).

[Paul Clapham]

Yup, I too have found that there's nothing like asking somebody else a question when you're suffering from that kind of blindness. That's what the Ranch is here for!