This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
It is said that intern() of String called on a String Object, first searches the same Object through its equals() in all available references in literal pool, and if not found then puts a reference of that String Object in literal pool , and returns the same reference to calling application.
As we know that String constant pool contains references of the Strings Objects allocated in heap not actual String Objects.
Here 'heapString' is on heap , and its reference is put in String literal pool when intern() is called on this. Same reference is returned to internedString. Then why I am getting result as "Different References" ?
Amit Kehri wrote: Here 'heapString' is on heap , and its reference is put in String literal pool when intern() is called on this.
A String with that value is put in the pool, but that doesn't change the heapString reference (since you never assign anything new to that). So your comparing a reference in the pool with one that's not in the pool - they're bound to be different.
(I assume the fact that one line refers to internedString and one refers to heapInternedString is a typo).