For example, 10! = 10 9 ... 3 2 1 = 3628800,
and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27.

Find the sum of the digits in the number 100!

I am trying to solve it but 100! is big even for long. I thought i can try to break the factorial in parts and then solve it but still in end i have to multiply all the results which overshoot the long.