problem with findinline function

[sparsh khandelwal]

try to write code to understand the function of findInLine function , but i failed to write a successful program.

import java.util.*;
class d{
public static void main(String args[]){
char a,b,c,d;
Scanner s=new Scanner(System.in);
a=s.findInLine(".").charAt(3);
b=s.findInLine(".").charAt(2);
c=s.findInLine(".").charAt(1);
d=s.findInLine(".").charAt(0);
System.out.println(a);
System.out.println(b);
System.out.println(c);
System.out.println(d);
}
}

what i try to do that if i give input "abcd" , then variable a will be = to d ,varibale b=c ,c=b and d=a (according to the input , but face a run time error)
please help

[Winston Gutkowski]

sparsh khandelwal wrote:what i try to do that if i give input "abcd" , then variable a will be = to d ,varibale b=c ,c=b and d=a (according to the input , but face a run time error)

First: when asking a question about an error, you should always specify what the error is, including providing the exact message. I have to admit to never having used findInLine(), but from what I see, I'd care to bet that yours is an IndexOutOfBoundsException.

Second: Your statement above is definitely NOT what I get from reading the API docs for findInLine(). Maybe you could explain why you think it works that way.

Winston

[sparsh khandelwal]

hey thank for your time
here comes the actual program , i modify this one to understand the working of findinline function but failed to do so :-)

import java.util.Scanner;
	class ReverseWord {
	public static void main(String args[]) {
	Scanner myScanner = new Scanner(System.in);
	char c1, c2, c3, c4;
		c1 = myScanner.findInLine(“.”).charAt(0);
		c2 = myScanner.findInLine(“.”).charAt(0);
		c3 = myScanner.findInLine(“.”).charAt(0);
		c4 = myScanner.findInLine(“.”).charAt(0);
	System.out.print(c4);
	System.out.print(c3);
	System.out.print(c2);
	System.out.print(c1);
	System.out.println();
	}
}

[Henry Wong]

sparsh khandelwal wrote:hey thank for your time
here comes the actual program , i modify this one to understand the working of findinline function but failed to do so :-)

Hate to point out the obvious, but can you guess what the error may be based on the exception that is returned???

Henry