scanner findInLine method

[Ankit Gareta]

Hi all,

         String input = "1 fish 2 fish red fish blue fish";
	     Scanner s = new Scanner(input);
	     s.findInLine("(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)");
	     MatchResult result = s.match();
	     for (int i=1; i<=result.groupCount(); i++)
	         System.out.println(result.group(i));
	     s.close(); 

output : 
1
2
red
blue

I can't understand the output, actually i m confused on "s.findInLine("(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)");" this line. what this line actually want to say ?

Thanks in advance.
Ankit

[Nikhil Sagar]

Ankit Gareta wrote:Hi all,

         String input = "1 fish 2 fish red fish blue fish";
	     Scanner s = new Scanner(input);
	     s.findInLine("(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)");
	     MatchResult result = s.match();
	     for (int i=1; i<=result.groupCount(); i++)
	         System.out.println(result.group(i));
	     s.close(); 

output : 
1
2
red
blue

I can't understand the output, actually i m confused on "s.findInLine("(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)");" this line. what this line actually want to say ?

Thanks in advance.
Ankit

In your case findInLine() says that-
Find, "(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)" in String s.

[Ankit Gareta]

Is this "(\\d+) fish (\\d+) fish (\\w+) fish (\\w+)" String pattern doesn't return only one token where the Scanner string is "1 fish 2 fish red fish blue fish" ?
because first one or more digit then fish(2 times), then one or more words then fish...that will get in whole line.