global and local variable concept

[bhavneet kaur]

 class C1 
{ 

    static int s; 

    public static void main(String a[]) 
    { 

          C1 obj=new C1(); 
          obj.m1(); 
          System.out.println(s); 
    } 

    void m1() 
    { 
          int x=1; 
          m2(x); 
          System.out.println(x+""); 
     } 

     void m2(int x) 
     { 
           x=x*2; 
           s=x; 
     } 
} 

//its output is :
1
2
why the value of x doesnt changed??

[Enkita mody]

bhavneet kaur wrote:
class C1
{

static int s;

public static void main(String a[])
{

C1 obj=new C1();
obj.m1();
System.out.println(s);
}

void m1()
{
int x=1;
m2(x);
System.out.println(x+"");
}

void m2(int x)
{
x=x*2;
s=x;

}
}

//its output is :
1
2
why the value of x doesnt changed??

Enkita mody
Ranch Hand

Joined: Aug 06, 2012
Posts: 294

I like...

x is a method local variable of m1.it doesn't belongs to m2 method.m2 has its own another x.

[bhavneet kaur]

it means if "s" would also be inside main function then it would also not changed

[Enkita mody]

bhavneet kaur wrote:
it means if "s" would also be inside main function then it would also not changed

s is a static variable, you can't declare it in static method main.

[bhavneet kaur]

but i have executed it again with s inside main still its giving same output

[bhavneet kaur]

why so i have declared it inside main as int s; so it becomes static because it is now declared inside static main method

[Enkita mody]

bhavneet kaur wrote:
why so i have declared it inside main as int s; so it becomes static because it is now declared inside static main method

No,int s is not a static variable until you write static int s.