sierra/bates ch.4 self test, question #2

[Rachel Glenn]

given the code segment:

        float [][] f2 = {{42.0f}, {1.7f, 2.3f}, {2.6f, 2.7f}};
        float [] f3 = {2.7f};

and the test for equality...

if (f2[2] == f3) {}

Is the reason the equality test COMPILES because f3 and f2[2] are considered object references? I initially thought this might not compile because the array sizes were different.

[Enkita mody]

R Gle wrote:given the code segment:

        float [][] f2 = {{42.0f}, {1.7f, 2.3f}, {2.6f, 2.7f}};
        float [] f3 = {2.7f};

and the test for equality...

if (f2[2] == f3) {}

Is the reason the equality test COMPILES because f3 and f2[2] are considered object references? I initially thought this might not compile because the array sizes were different.

Yes.You're comparing their address not any element.


-hth

[Praveen Kumar M K]

R Gle wrote:given the code segment:

        float [][] f2 = {{42.0f}, {1.7f, 2.3f}, {2.6f, 2.7f}};
        float [] f3 = {2.7f};

and the test for equality...

if (f2[2] == f3) {}

Is the reason the equality test COMPILES because f3 and f2[2] are considered object references? I initially thought this might not compile because the array sizes were different.

f2 is an array of arrays, therefore the individual elements within this collection should also be arrays, correct? So when you access f[2] you are accessing an array at the 2nd position, so it should compile.
How about trying if(f2 == f3) {}?