Failed to map to jsp file.

[sam White]

Hi With Spring mvc 3.0.5 and jsp, my DispatcherSerlvet thrown the following exception:

19:26:36,778 WARN [org.springframework.web.servlet.PageNotFound] (http--192.168.1.20-8080-13) No mapping found for HTTP request with URI [/LuxuryLiving-web/WEB-INF/views/home.jsp] in DispatcherServlet with name 'dispatcherServlet'

Here is my xml config file:

<?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <filter> <filter-name>characterEncodingFilter</filter-name> <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class> <init-param> <param-name>encoding</param-name> <param-value>UTF-8</param-value> </init-param> <init-param> <param-name>forceEncoding</param-name> <param-value>true</param-value> </init-param> </filter> <filter-mapping> <filter-name>characterEncodingFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/spring/root-context.xml /WEB-INF/spring/appServlet/security-config.xml </param-value> </context-param> <!-- Creates the Spring Container shared by all Servlets and Filters --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> <!-- Processes application requests --> <servlet> <servlet-name>dispatcherServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/spring/appServlet/servlet-context.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> <multipart-config> <max-file-size>20480000</max-file-size> <max-request-size>20480000</max-request-size> </multipart-config> </servlet> <servlet-mapping> <servlet-name>dispatcherServlet</servlet-name> [b]<url-pattern>/*</url-pattern>[/b] </servlet-mapping> </web-app>

Controller class:

@Controller
public class CategoryController {

    private static final Logger logger = Logger.getLogger(CategoryController.class);
    
    private CategoryService categoryService;
    private AdminService adminService;
    
    @Autowired
    public CategoryController(CategoryService categoryService, AdminService adminService) {
        this.categoryService = categoryService;
        this.adminService = adminService;
    }

  
    @RequestMapping(value = "/", method = RequestMethod.GET)
    public String home(HttpServletRequest request, Locale locale, Model model) {
        logger.debug(" =======HOME PAGE========");
        List<CategorySubcategories> categories = (List<CategorySubcategories>) categoryService.findAll();
        logger.debug("====categories: "+categories.size());
	model.addAttribute("categories", categories);

        return "/home";
    }
}

In my xml config file, when I used "<url-pattern>/abc/*</url-pattern>" mapping, there is no problem until I changed it to "/*", then it failed to map to the correct jsp file.
How can I use /* mapping instead of /abc/*?

I want my website to be browsed as "www.mysite.com" rather than "www.mysite.com/abc/"

Any suggestion is very appreciated
Thanks
Sam

[sam White]

I changed it to <url-pattern>/</url-pattern>, then it works . But my login doesn't work with the following error:

HTTP Status 404 - /j_spring_security_check

type Status report

message /j_spring_security_check

description The requested resource (/j_spring_security_check) is not available.

JBoss Web/7.0.13.Final

This is my secuirty-config.xml file:

<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:tx="http://www.springframework.org/schema/tx" xmlns:security="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd"> <!-- Configure Spring Security --> <security:http auto-config="true" use-expressions="true" access-denied-page="/auth/denied" > <security:intercept-url pattern="/auth/login" access="permitAll"/> <security:intercept-url pattern="/admin" access="hasRole('ROLE_ADMIN')" /> <!-- <security:intercept-url pattern="/j_spring_security_check" access="ROLE_SUPERVISOR" />--> <security:form-login login-page="/auth/login" authentication-failure-url="/auth/login?error=true" default-target-url="/admin"/> <security:logout invalidate-session="true" logout-success-url="/" logout-url="/auth/logout"/> </security:http> <security:authentication-manager> <!-- Declare an authentication-manager to use a custom userDetailsService --> <security:authentication-provider user-service-ref="customUserDetailsService"> <security:password-encoder ref="passwordEncoder"/> </security:authentication-provider> </security:authentication-manager> <context:annotation-config /> <!-- Use a Md5 encoder since the user's passwords are stored as Md5 in the database --> <!-- <bean class="org.springframework.security.authentication.encoding.Md5PasswordEncoder" id="passwordEncoder"/>--> <!-- use BCrypt encoder --> <bean class="org.springframework.security.crypto.bcrypt.BCryptPasswordEncoder" id="passwordEncoder"/> <!-- A custom service where Spring will retrieve users and their corresponding access levels --> <bean id="customUserDetailsService" class="LuxuryLiving.manager.service.CustomUserDetailsService" /> <context:component-scan base-package="LuxuryLiving" annotation-config="true" /> </beans>

controller for handling login:

@Controller
@RequestMapping("/auth")
public class LoginLogoutController {
        
	protected static Logger logger = Logger.getLogger("LoginLogoutController.class");

        private AdminService adminService;
        
        @Autowired
        public LoginLogoutController(AdminService adminService) {
            this.adminService = adminService;
        }
 	/**
	 * Handles and retrieves the login JSP page
	 * 
	 * @return the name of the JSP page
	 */
	@RequestMapping(value = "/login", method = RequestMethod.GET)
	public String getLoginPage(@RequestParam(value="error", required=false) boolean error, 
			ModelMap model) {
		logger.debug("Received request to show login page");

		// Add an error message to the model if login is unsuccessful
		// The 'error' parameter is set to true based on the when the authentication has failed. 
		// We declared this under the authentication-failure-url attribute inside the spring-security.xml
		/* See below:
		 <form-login 
				login-page="/krams/auth/login" 
				authentication-failure-url="/krams/auth/login?error=true" 
				default-target-url="/krams/main/common"/>
		 */
		if (error == true) {
			// Assign an error message
			model.put("error", "You have entered an invalid username or password!");
		} else {
			model.put("error", "");
		}
		
		// This will resolve to /WEB-INF/jsp/loginpage.jsp
		return "/loginpage";
	}
	
	/**
	 * Handles and retrieves the denied JSP page. This is shown whenever a regular user
	 * tries to access an admin only page.
	 * 
	 * @return the name of the JSP page
	 */
	@RequestMapping(value = "/denied", method = RequestMethod.GET)
 	public String getDeniedPage() {
		logger.debug("Received request to show denied page");
		
		// This will resolve to /WEB-INF/jsp/deniedpage.jsp
		return "/deniedpage";
	}

Looking forward to your suggestion.
Thanks
Sam