doubt with this shell script unix command

[preethi kumar]

find . -name "*" -type f gives me the below output

./test3.php
./test2.php
./test1.php


i want to pipe some command in such a way that my output should be

test3.php
test2.php
test1.php

and the number of php files and lines can change. so how do i write a general linux command?

[Jeanne Boyarsky]

There are a number of ways to do this. The one I think of is to use sed to remove the first two characters from each line:

find . -name "*" -type f | sed 's/^..//'

[Stefan Wagner]

find . -name "*" -type f -printf "%f\n"

This works for gnu-find. Your find might differ.

Instead of piping, it is often, but not always, a good idea, to use one of the switches: -exec, -execdir, -ok, -okdir. It isn't trivial to use, but powerful.

[preethi kumar]

Thank you guys. your response really helped .