Please help to Understand How Increment and Decrement works

[rayan alex]

Hi Please help to understand this out put of this

int x=10; 	
x=++x+ + +x+x++;

I counted the output as 35. But correct out put 33. Please help to understand.

This is how i counted.

++x uses incremented value. So first ++x = 11
next ++x increment x again. so second ++x = 12
next x++ uses the current value in the memory. so uses 12. 11 + 12 + 12 = 35


Thank you

[Rameshwar Soni]

Since you are telling first there is ++x then there is ++x and finally x++, so the way you have written your expression is incorrect.

So instead of this

x=++x+ + +x+x++;  

write your expression neatly i.e.

x = ++x + ++x + x++;

you will surely get the output as 35.

[rayan alex]

Hi,

Thank you for your reply. But correct out put is 33. I tried to say im getting 35.
I trying to figure out why i'm not getting 33 with my calculation.

[Henry Wong]

rayan alex wrote:

int x=10; 	
x=++x+ + +x+x++;

I counted the output as 35. But correct out put 33. Please help to understand.

This is how i counted.

++x uses incremented value. So first ++x = 11
next ++x increment x again. so second ++x = 12
next x++ uses the current value in the memory. so uses 12. 11 + 12 + 12 = 35

There is no "next ++x" (ie. second pre-increment). There is a space between the two plus signs. It is not a pre-increment, it is two unary plus operators. So, the correct expressions with precedence (and associativity) applied should be...

x= ((++x) + (+ (+x))) + (x++);

Henry