executor

[meeta gaur]

import java.util.concurrent.Executors;
import java.util.concurrent.Executor;

class ExecutorExample implements Runnable
{
	public void run(){
		System.out.println(Thread.currentThread().getName());
	}
	public static void main(String[] args) 
	{
		 	 ExecutorExample obj=new ExecutorExample();

			 Executor e=Executors.newFixedThreadPool(3);
			 e.execute(obj);
	 		 e.execute(obj);
	}
}

pool-1-thread-2
pool-1-thread-1

why doesn't program stop ? why does it hang after above output?

and another thing, i invoked execute method two times, does it mean it will start two new threads using only one executor object?

[Emanuel Kadziela]

The program doesn't stop because the Executor is still running. Try e.shutdownNow() at the end of your code snippet.

When you called Executors.newFixedThreadPool(3) you created an executor with 3 threads (read the javadocs). When you call execute() it uses one of those 3 threads to execute the runnable.

[meeta gaur]

Emanuel Kadziela wrote:The program doesn't stop because the Executor is still running. Try e.shutdownNow() at the end of your code snippet.

When you called Executors.newFixedThreadPool(3) you created an executor with 3 threads (read the javadocs). When you call execute() it uses one of those 3 threads to execute the runnable.

Thanks.I am using Executor interface not ExecutorSerive interface.It hasn't any shutdown method.

ExecutorExample1.java:17: error: cannot find symbol
e.shutdownNow();
^
symbol: method shutdownNow()
location: variable e of type Executor
1 error

[Jelle Klap]

Then you should probably switch to the ExecutorService interface.

[Emanuel Kadziela]

Please read the javadocs

And just change this:

Executor e=Executors.newFixedThreadPool(3); 

to this:

ExecutorService e=Executors.newFixedThreadPool(3); 

[meeta gaur]

Yes i will use that.Seems Executor is useless, a car without break.

[sajid toor]

now i know,thanks for sharing.