Problem in Exception

[Irfan Zubair]

class A{ 
public void methodA() throws Exception{ 
try{ 
System.out.println("5"); 
throw new Exception(); 
System.out.println("2"); 
}
finally{ 
System.out.println("3"); 
} 
} 
} 
public class MyClass{ 
public static void main(String[] args) 
{ 
A a=new A(); 
try { 
a.methodA(); 
} catch (Exception e) { 
System.out.println("4");
} 
} 
}

I don't know why I am getting this error.

MyClass.java:6: unreachable statement
System.out.println("2");
^
1 error

Can anyone tell me why?

[fred rosenberger]

first, let's format this correctly:

class A
{   
  public void methodA() throws Exception
  {   
    try
    {   
      System.out.println("5");   
      throw new Exception();   
      System.out.println("2");   
    }  
    finally
    {   
      System.out.println("3");   
    }   
  }   
}   
public class MyClass
{   
  public static void main(String[] args)   
  {   
    A a=new A();   
    try 
    {   
      a.methodA();   
    }
    catch (Exception e) 
    {   
      System.out.println("4");  
    }   
  }   
}  

Now...how exactly do you think you can reach line 9? As soon as you throw the exception on line 8, you jump to the finally block on line 11. So there is no possible way for this line to execute. The compiler can tell, and assumes that you made a mistake somewhere.