Unicode Representation

[sr shashidhar]

Hi frnds,

public class unic {
	
public static void main(String[] args) {
	float f=\u0038f;
	int i=\u0038;

	float f1='\u0038';
	int i1='\u0038';

	System.out.println(f);
	System.out.println(i);

	System.out.println(f1);
	System.out.println(i1);

OUTPUT
---------
8.0
8

56.0
56

My question is how we are getting 8 and 56 for '\u0038'...?


thanks in advance

[Campbell Ritchie]

I trust you know that 38hex means 56dec?
So your compiler goes through the code, and converts all your Unicode escapes to displayed characters. Your \u0038 becomes 8 and your '\u0038' becomes '8'. That is done before you compile anything. I presume you can work out how 8f becomes 8.0 and how '8' becomes 56, now.

[Ivan Jozsef Balazs]

(too slow - deleted)

[Tony Docherty]

The unicode character \u0038 is '8' so in the first case the value 8 is assigned to the variable. In the second case you are assigning the char with a value of \u0038. This is a Hex value which when converted to decimal is 56.

Edit: Even slower

[sr shashidhar]

Now i got.
Thanks Campbell Ritchie , Tony Docherty

[Campbell Ritchie]

You’re welcome