I Wonder How To Catch This Exception ?

[Ranjith Suranga]

Hi, I have got this code in my class. I have tried to catch the exception here, but i am still not able to do it so.. Could you please help me... ?

class A{
	void myMethod(){
		System.out.println("Call myMethod");
		myMethod();
	}
}
class Demo{
	public static void main(String args[]){
		System.out.println("Start");
		A a1=new A();
		a1.myMethod();
		System.out.println("End. :");
	}
}

These are the methods which I have tried to catch the exception.. Non of them work in this case.. I don't know why... ?

class A{
	void myMethod(){
		System.out.println("Call myMethod");
		try{
			myMethod();
		}catch(Exception exp){
			System.out.println(exp.getMessage());
		}
	}
}
class Demo{
	public static void main(String args[]){
		System.out.println("Start");
		A a1=new A();
		a1.myMethod();
		System.out.println("End. :");
	}
}

class A{
	void myMethod()throws Exception{
		System.out.println("Call myMethod");
		myMethod();
	}
}
class Demo{
	public static void main(String args[]){
		System.out.println("Start");
		A a1=new A();
		try{
			a1.myMethod();
		}catch(Exception exp){
			exp.printStackTrace();
		}
		System.out.println("End. :");
	}
}

Thank You.

[Ranjith Suranga]

Hey, Isn't this exception ? Is this an error... ?

[Ranjith Suranga]

OK. I tried this and it works.. It is not an exception, It is an error, I think...

class A{
	void myMethod(){
		System.out.println("Call myMethod");
		try{
			myMethod();
		}catch(Error err){
			err.printStackTrace();
		}
	}
}
class Demo{
	public static void main(String args[]){
		System.out.println("Start");
		A a1=new A();
		a1.myMethod();
		System.out.println("End. :");
	}
}

[Campbell Ritchie]

Never catch Errors (unless you are simply seeing what happens if…).

I would rather say, “What Exception?” I can’t see anything which produces a bona fide Exception in your code.
You are recursively calling a method with no base case, so your recursion will go on for ever (or more precisely until you exhaust the available stack memory), but that is a different design mistake.