how to iterate response object in a table

[Abdul Wahab]

hi ranchers,
I am submitting a form via Jquery Ajax post method and i get a response object(list of rows from database) successfully.
i dont know how to set the response values in a table.

$(function() {
	 
		$('#articledialog').dialog({ 
		autoOpen: false,
		width: 610,
        height: 600,
        resizable: true,
        autoResize: true,  
        buttons:{
            Save: function(){   
            	var ctno = $('#prf_contractno').val();
            	var form = $("#PrfArticle");
            	dataString = form.serialize()+ "&ctno=" + ctno;
            	$.ajax({
            		url:"/Myelclass/PrfinsertArticle.do",
            		type: "POST",
            		async:false,
            		data: dataString,
            		success:function(result){
            			//alert(dataString);
            			alert("Form Submitted: " + result); 
            			//$("#result").html(data);  //not working
            			 $('#articledialog').dialog('close');
            		},
            		error: function(xhr, textStatus, errorThrown) {
            			alert('An error occurred! ' + errorThrown);
            			$(this).dialog('close'); 
            			},
            		
            	});
            }, 
           Cancel: function(){       	  
            	   $(this).dialog('close'); 	
              },//end of cancel    
       	 	},  //end of button
        }); //end of dialog event	


<div id="result">
          		<table id="tblprfarticle"  border="2"  >
                		<thead>
                		 <tr>
                   		<th >Article</th>
                   		<th >Color</th>
                   		<th >Size</th>
                   		<th >Subs</th>
                   		<th >Sel</th>
                   		<th >Selection %</th>
                   		<th >Quantity</th>
                   		<th >Price</th>
                   		<th >TC</th>	
                   	</tr>
        				</thead>
        				<tbody>
                   	<c:forEach items="${article}" var="artdet">
                 	<tr>
                   		<td><c:out value="${artdet.prf_articlename }"></c:out></td>
                   		<td><c:out value="${artdet.prf_color }"></c:out></td>
                   		<td><c:out value="${artdet.prf_size }"></c:out></td>
                   		<td><c:out value="${artdet.prf_substance }"></c:out></td>
                   		<td><c:out value="${artdet.prf_selection }"></c:out></td>
                   		<td><c:out value="${artdet.prf_selectionp }"></c:out></td>
                   		<td><c:out value="${artdet.prf_quantity }"></c:out></td>
                   		<td><c:out value="${artdet.prf_price }"></c:out></td>
                   		<td><c:out value="${artdet.prf_tc }"></c:out></td>    		
                 	</tr>
                 	</c:forEach>
               	</tbody>
               		</table>
              		</div>

Any help..

[Bear Bibeault]

What's be easiest is to have the server, perhaps using a JSP, format the table rows to send as the response. Then the HTML fragment can simply be injected into the DOM.

If not that, then what are you getting back as the response? JSON data? if so, you'll need to create all the DOM elements yourself using jQuery's DOM creation capabilities.

[Abdul Wahab]

If not that, then what are you getting back as the response? JSON data? if so, you'll need to create all the DOM elements yourself using jQuery's DOM creation capabilities.

hmm.. not json..i am trying to convert to json..below is my code.. can you help me with that..

 //Check for Successfull Insertion if Yes get all records
				 if(isarticlesaved == 1){
					 List<PrfArticlebean> articlelist = prfbo.getPrfArticleDetails(ctno);
					 //JSONArray jsArray = new JSONArray(article); 
					JSONObject  json = new JSONObject();
					 json.accumulate("articlelis", articlelist );
					 System.out.println(json.toString());
					
					 out.println(json);
				 }    

[Bear Bibeault]

What is the response returning?

[Abdul Wahab]

An error occurred! SyntaxError: JSON.parse: unexpected character.. this is the error i am recieving..where am i wrong???

[Bear Bibeault]

Bear Bibeault wrote:What is the response returning?

[Abdul Wahab]

Actually bear when try without json (normal object) i am getting sucessfull result
out put

Form Submitted: [sb.elpro.model.PrfArticle@76539f0d, sb.elpro.model.PrfArticle@6bef4b2b, sb.elpro.model.PrfArticle@2b302b69, sb.elpro.model.PrfArticle@677210a5]

but when i try to convert to json i am getting the following error

SyntaxError: JSON.parse: unexpected character.. this is the error i am recieving..where am i wrong??? 

[Abdul Wahab]

And what is the main difference between attributes in servlet (set or getAttribute) and json. both are object right??

[Bear Bibeault]

Abdul Wahab wrote:Actually bear when try without json (normal object) i am getting sucessfull result
out put

That's not valid JSON. So of course, it cannot be converted. You'll need to fix the server code to return valid JSON. There are many Java JSON libraries to choose from.

[Abdul Wahab]

That's not valid JSON. So of course, it cannot be converted. You'll need to fix the server code to return valid JSON

yes! you are right