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Spring HandlerExceptionResolver implementations deal with unexpected exceptions that occur during controller execution. A HandlerExceptionResolver somewhat resembles the exception mappings you can define in the web application descriptor web.xml. However, they provide a more flexible way to do so. For example they provide information about which handler was executing when the exception was thrown. Furthermore, a programmatic way of handling exceptions gives you more options for responding appropriately before the request is forwarded to another URL (the same end result as when you use the Servlet specific exception mappings).
Look at the bold sentence. My question is how to get the information of the executing handler?
And for the next paragraph:
Besides implementing the HandlerExceptionResolver interface, which is only a matter of implementing the resolveException(Exception, Handler) method and returning a ModelAndView, you may also use the provided SimpleMappingExceptionResolver or create @ExceptionHandler methods. The SimpleMappingExceptionResolver enables you to take the class name of any exception that might be thrown and map it to a view name. This is functionally equivalent to the exception mapping feature from the Servlet API, but it is also possible to implement more finely grained mappings of exceptions from different handlers. The @ExceptionHandler annotation on the other hand can be used on methods that should be invoked to handle an exception. Such methods may be defined locally within an @Controller or may apply globally to all @RequestMapping methods when defined within an @ControllerAdvice class. The following sections explain this in more detail.
I don't understand the sentence: it is also possible to implement more finely grained mappings of exceptions from different handlers.
What does that mean, and could any one give me some examples to illustrate that statement?
Thanks in advance.
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subject: Doubt about exceptions handling in Spring