Determine included JSP page name and load JSP into specified section using jQuery
posted 3 years ago
Hi guys, I'm working on a web projects, but now i encounter this problem.
My main page main.jsp includes several different pages to make it up (please see the attachment).
when i click a item resides in the MENU, I use jQuery to load specified page into CONTENT:
partial code segment of menu.jsp:
Now the question is, i want to show "current location" in NAVIGATION, e.g, "current location: Main Page", "current location: Main >> User Mgmt >> Add User";
the concatenated string "Main Page" or "Main >> User Mgmt >> Add User" is dynamically determined by looking up a Map<page url, concatenated string>,
so I must get the page url loaded into CONTENT('#content'), which is part of the main page main.jsp.
How to get my job done?
THEN, the next question is as follows.
when i loaded a page, e.g., adduser.jsp, into CONTENT, and I submit it using jQuery, it doesn't work(and no any alert message occurs):
code segment from adduser.jsp(the form's id is 'auform'):
as the code illustrates, load the same page into original location CONTENT ('#content') when submit successfully.
but now, it redirect to content.jsp, which is included into main.jsp at startup.
and i notify the "url addr" of the submit button of adduser.jsp is exactly "main.jsp", why?
upon login, in my servlet code, i use the following code to "redirect" to my main page:
the reason I use this method is that if i use request.getRequestDispatcher("main.jsp").forward(request, response);,
the url in the browser's address bar is http://xxxxx/UserServlet?action=login .
in my login.jsp, the form's post action is "action="UserServlet?action=login""...
so are these phenomena related? Thanks in advance, and sorry for my poor English.