aspose file tools*
The moose likes Other Languages and the fly likes Assembly Language Help. Little Man Computer Program Big Moose Saloon
  Search | Java FAQ | Recent Topics | Flagged Topics | Hot Topics | Zero Replies
Register / Login


Win a copy of Spring in Action this week in the Spring forum!
JavaRanch » Java Forums » Languages » Other Languages
Bookmark "Assembly Language Help. Little Man Computer Program " Watch "Assembly Language Help. Little Man Computer Program " New topic
Author

Assembly Language Help. Little Man Computer Program

Ryan Hickman
Ranch Hand

Joined: Oct 13, 2012
Posts: 36
I am trying to write two different programs in LMC using an old assembly language. The first as is follows:



Writea LMC program that takes two inputs, a number to count down from, and the stepvalue (example: count down from 35 by 5), until it reaches zero. It should print each step, and the lastnumber before zero if the sequence doesn’t end on zero, but if the number goesto negative, that number should not be printed. Example output using 13 and 3 as inputs would be: 13, 10, 7, 4, 1. Example output using 12 and 3 as inputs wouldbe: 12, 9, 6, 3, 0.



I have tried something along the lines of this:



IN

STO 91

IN

STO 92

IN

STO 93

LDA 91

ADD 92

SUB 93

OUT

HLT



Which does not work



The second LMC program I am trying to write is as follows:



Writethe code to calculate the area and perimeter of a triangle. The program should take 3 inputs, which are,in order, the base, height, and the third side of the triangle. The code shouldproduce 2 values in the output box, the first number will be the area and thesecond, the perimeter. (Hint: you’ll probably want to use DAT statements tostore some values to start).



I do not even know where to start on this one.



Any help would be appreciated.



I found a working simulator at this website:



http://www.itk.ilstu...lmc/default.htm




I also have some example codes to help:

Calculate perimeter & area - takes L & W as inputs
prints out perimeter first, then area.
00 LDA #01;
01 STA 99;
02 IN;
03 STA 98;
04 LDA #00;
05 STA 96;
06 IN;
07 STA 97;
08 ADD 97;
09 ADD 98;
10 ADD 98;
11 OUT;
12 LDA 96;
13 ADD 98;
14 STA 96;
15 LDA 97;
16 SUB 99;
17 STA 97;
18 SKZ;
19 JMP 12;
20 LDA 96;
21 OUT;
22 HLT;


MULTIPLIES TWO NUMBERS.
00 IN;
01 STA 99;
02 STA 97;
03 IN;
04 STA 98;
05 SUB 90;
06 STA 98;
07 SKZ;
08 JMP 12;
09 LDA 97;
10 OUT;
11 HLT;
12 LDA 97;
13 ADD 99;
14 STA 97;
15 LDA 98;
16 JMP 05;
90 DAT 001;

ADDS THE FIRST NUMBER INPUT TO ITSELF,
THEN SUBTRACTS THE SECOND INPUT FROM THE TOTAL
00 IN;
01 STA 90;
02 IN;
03 STA 91;
04 LDA 90;
05 ADD 90;
06 SUB 91;
07 OUT;
08 HLT;

ONE WAY OF COUNTING FROM AN INPUT DOWN TO ZERO
00 IN;
01 OUT;
02 SUB 98;
03 SKP;
04 JMP 06;
05 JMP 01;
06 HLT;
98 DAT 002;




SQUARING A NUMBER
00 IN; take input

01 STA 99; save value as a mulitiplier

02 STA 97; save value as multiplicand

03 SUB 90; subtract one from counter

04 STA 98; copy value to counter

05 LDA 97; load our accumulator number

06 ADD 99; Add original number

07 STA 97; store intermediate sum

08 LDA 98; Load counter

09 SUB 90; subtract one from counter

10 STA 98; Store counter value

11 SKZ; skip if counter is at zero

12 JMP 05; othewise, loop back to 5

13 LDA 97; load our squared number

14 OUT; Write output

15 HLT; stop

90 DAT 01; countdown value
Michael Dangelo
Greenhorn

Joined: Oct 14, 2013
Posts: 1
Im in this same class, although Im not gonna give you the answer I'll give some hints.

First a few errors in your coding:

The Store command is STA not STO

You have to number all your code lines starting with 00
EX. 00 IN

You only have 2 inputs for the first part, so you cant read in 3 times.

Now some hints:

Try subtracting the second number that was stored from the first number then restoring in the same slot. Then use the SKN coupled with the JMP command to reiterate your code...like a loop. That way it will keep subtracting until it hits negative, and dont forget to output each number.

For the Triangle one the area is 1/2(base * Height) just think about what multiplication is in Addition. (Use a counter). The first part is to get you ready for the second part, remember that. For division the dividing factor is by two so use a counter like in multiplication but subtract the numbers instead of add and deduct from the counter by 2 instead of 1.
Campbell Ritchie
Sheriff

Joined: Oct 13, 2005
Posts: 39409
    
  28
Welcome to the Ranch

Good idea to give hints like that.
 
I agree. Here's the link: http://aspose.com/file-tools
 
subject: Assembly Language Help. Little Man Computer Program