Values not retireved using rownum in oracle

[Prashanth Chandra]

Hi All,
I have writte a query which retirves data from table using the rownum attribute which works fine:

select * from (select id,count(*) from average a where rownum <= (select count(*) from average) group by id) where rownum < 65501

But when I am trying to retieve the value above 65501 I am not able to fetch the records from the table. Please fine the below which is not working

select * from (select id,count(*) from average a where rownum <= (select count(*) from average) group by id) where >= 65501

Can anyone please let me know how I can retireve the data based on the above query.

Thanks in advance
regards
Prashanth

[Avi Abrami]

Prashanth,
If I remember correctly, Oracle only allows less than or equal to logical operators with rownum pseudo-column.
Hence your query using greater than operator does not work.
I'm only guessing, but I think you may be able to use the "between" operator, as in:

rownum between 65501 and 100000

Good Luck,
Avi.

[Paul Campbell]

This is your original query (see the comments next to your code):

 select * 
  from (select id,count(*) 
          from average a 
         where rownum <= (select count(*) //this subquery when combined with
                            from average)    
                                             // the where clause states you
                                             // want to include the row from the average table 
                                             // if it is <= the number
                                             // of rows within the average table
                                             // this is a useless subquery by the way.
        group by id) //if your ID is unique... your count is 1 for each ID
  where rownum < 65501 //do you have more than 65,501 unique IDs?   

Run the following:

select distinct count(id)
  from average

to find the total number of rows associated with the ID group by clause... but as written... you are always showing the numbers for all your rows grouped by ID.
[ October 30, 2008: Message edited by: Paul Campbell ]