This week's book giveaway is in the OO, Patterns, UML and Refactoring forum. We're giving away four copies of Refactoring for Software Design Smells: Managing Technical Debt and have Girish Suryanarayana, Ganesh Samarthyam & Tushar Sharma on-line! See this thread for details.
Hi all, Am new bee to this space.I am having difficulty in running a simple servlet on Tomcat 4.1.The following are my directory Structures. TOMCAT_HOME = D:/Program Files/Apache Group/Tomcat4.1 My html fine index.html is in %TOMCAT_HOME%/webapps/greetings My GreetingServlet.class is in %TOMCAT_HOME%/webapps/WEB-INF/classes I am calling the GreetingServlet from index.html as ACTION="/greetings/servlet/GreetingServlet" My web.xml looks like this <?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd"> <web-app> <servlet> <!-- Servlet Alias --> <servlet-name>Registration</servlet-name> <!-- fully qualified servlet class --> <servlet-class>GreetingServlet</servlet-class> </servlet>
</web-app> When i run the index.html and try to call the servlet am getting 404 /greetings/servlet/GreetingServlet not found.
Can anyone tell me what i am missing here??.Is there any other place where i need to register my servlet??. This code exercise is taken from Profession Java Server Programming from Wrox Publications. Thanks in advance, Ramnath
This form of addressing (using /servlet/) requires the invoker servlet - this has to be THE most common problem with Tomcat 4 - look around some of the recent posts for a discussion. You really should put all servlet and helper classes into a package - it will save you much grief. Bill [ July 29, 2003: Message edited by: William Brogden ]
I’ve looked at a lot of different solutions, and in my humble opinion Aspose is the way to go. Here’s the link: http://aspose.com