Tom CAT help

[Ramnath krishnamurthi]

Hi all,
Am new bee to this space.I am having difficulty in running a simple servlet on Tomcat 4.1.The following are my directory Structures.
TOMCAT_HOME = D:/Program Files/Apache Group/Tomcat4.1
My html fine index.html is in %TOMCAT_HOME%/webapps/greetings
My GreetingServlet.class is in %TOMCAT_HOME%/webapps/WEB-INF/classes
I am calling the GreetingServlet from index.html as
ACTION="/greetings/servlet/GreetingServlet"
My web.xml looks like this
<?xml version="1.0" encoding="ISO-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
<servlet>
<!-- Servlet Alias -->
<servlet-name>Registration</servlet-name>
<!-- fully qualified servlet class -->
<servlet-class>GreetingServlet</servlet-class>
</servlet>

</web-app>
When i run the index.html and try to call the servlet am getting
404 /greetings/servlet/GreetingServlet not found.

Can anyone tell me what i am missing here??.Is there any other place where i need to register my servlet??.
This code exercise is taken from Profession Java Server Programming from Wrox Publications.
Thanks in advance,
Ramnath

[Debashish Chakrabarty]

You will need to add a servlet mapping in deployment descriptor of your web-application (web.xml), something like this:

<servlet-mapping>
    <servlet-name>Registration</servlet-name>
    <url-pattern>/greetings/servlet/*</url-pattern>
</servlet-mapping>  

Did it help?
[ July 29, 2003: Message edited by: Debashish Chakrabarty ]

[Cindy Glass]

Moving to the Tomcat forum.

[William Brogden]

ACTION="/greetings/servlet/GreetingServlet"

This form of addressing (using /servlet/) requires the invoker servlet - this has to be THE most common problem with Tomcat 4 - look around some of the recent posts for a discussion.
You really should put all servlet and helper classes into a package - it will save you much grief.
Bill
[ July 29, 2003: Message edited by: William Brogden ]