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Where to put bean class in Tomcat?

Mary Gates
Greenhorn

Joined: Mar 20, 2005
Posts: 7
Hello All,
I create a jsp under tomcat and put it to webapps/Root directory.
It runs fine.
Then I created a bean class for the jsp page. Where shoud I put the compiled class? I put it to Root/Web-inf/classes. it still complains it could not find the class.
Thanks

here are the files:

getname.jsp

<HTML>
<BODY>
<FORM METHOD=POST ACTION="SaveName.jsp">
What's your name? <INPUT TYPE=TEXT NAME=username SIZE=20><BR>
What's your e-mail address? <INPUT TYPE=TEXT NAME=email SIZE=20><BR>
What's your age? <INPUT TYPE=TEXT NAME=age SIZE=4>
<P><INPUT TYPE=SUBMIT>
</FORM>
</BODY>
</HTML>

UserData.java
public class UserData {
String username;
String email;
int age;

public void setUsername( String value )
{
username = value;
}

public void setEmail( String value )
{
email = value;
}

public void setAge( int value )
{
age = value;
}

public String getUsername() { return username; }

public String getEmail() { return email; }

public int getAge() { return age; }
}


SaveName.jsp
<jsp:useBean id="user" class="UserData" scope="session"/>
<jsp:setProperty name="user" property="*"/>
<HTML>
<BODY>
<A HREF="NextPage.jsp">Continue</A>
</BODY>
</HTML>

NextPage.jsp

<jsp:useBean id="user" class="UserData" scope="session"/>
<HTML>
<BODY>
You entered<BR>
Name: <%= user.getUsername() %><BR>
Email: <%= user.getEmail() %><BR>
Age: <%= user.getAge() %><BR>
</BODY>
</HTML>


The error I got is:
org.apache.jasper.JasperException: /SaveName.jsp(1,1) The value for the useBean class attribute UserData is invalid.
org.apache.jasper.compiler.DefaultErrorHandler.jspError(DefaultErrorHandler.java:39)
org.apache.jasper.compiler.ErrorDispatcher.dispatch(ErrorDispatcher.java:405)
org.apache.jasper.compiler.ErrorDispatcher.jspError(ErrorDispatcher.java:146)
org.apache.jasper.compiler.Generator$GenerateVisitor.visit(Generator.java:1223)
org.apache.jasper.compiler.Node$UseBean.accept(Node.java:1116)
org.apache.jasper.compiler.Node$Nodes.visit(Node.java:2163)
org.apache.jasper.compiler.Node$Visitor.visitBody(Node.java:2213)
org.apache.jasper.compiler.Node$Visitor.visit(Node.java:2219)
org.apache.jasper.compiler.Node$Root.accept(Node.java:456)
org.apache.jasper.compiler.Node$Nodes.visit(Node.java:2163)
org.apache.jasper.compiler.Generator.generate(Generator.java:3270)
org.apache.jasper.compiler.Compiler.generateJava(Compiler.java:189)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:267)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:255)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:556)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:296)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:291)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:241)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)


Thanks a lot.
Craig Jackson
Ranch Hand

Joined: Mar 19, 2002
Posts: 405
I believe you must place the javabean in a package.
Mary Gates
Greenhorn

Joined: Mar 20, 2005
Posts: 7
Thanks... That works well...
 
I agree. Here's the link: http://ej-technologies/jprofiler - if it wasn't for jprofiler, we would need to run our stuff on 16 servers instead of 3.
 
subject: Where to put bean class in Tomcat?
 
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