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The file or folder 'java.exe. that this shortcut refers to cannot be found

Niyas Ahmed Sheikh
Ranch Hand

Joined: Jun 15, 2005
Posts: 129
I have installed JDK1.5 in C:\JDK1.5.
I have installed Tomcat 4.1 in C:\Tomcat.

SET PATH="C:\jdk1.5\bin;"%PATH%
SET JAVA_HOME="C:\jdk1.5;"%PATH%
SET CLASSPATH=".;C:\Tomcat\common\lib\servlet.jar;"%PATH%

While I tried to start the Tomcat thru the Start>>Programs>>Apache Tomcat 4.1>>start tomcat, I am getting this error message.

While I tried to start te tomcat thru' the MS-Dos
C:\cd Tomcat
C:\Tomcat>cd bin

I am getting the following error message:

What is the problem? Whether any problem in the path setting.
Bear Bibeault
Author and ninkuma

Joined: Jan 10, 2002
Posts: 61092

Moved to the Tomcat forum.

Why on earth are you appending PATH to JAVA_HOME?

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William Brogden
Author and all-around good cowpoke

Joined: Mar 22, 2000
Posts: 12769
You get that message when this test fails:

but if CATALINA_HOME is not defined, startup.bat makes a guess of ".."
which should work in your case. So it is seeing CATALINA_HOME but creating an error. I suspect it is due to the trailing ";" in your SET CATALINA_HOME statement. This variable is not dissassembled using ";"
The batch file will NOT discard that so you get an unusable path.
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