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creating .class file in Tomcat
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deepak borole
Greenhorn
Joined: Nov 13, 2005
Posts: 25
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hi I am trying to compile a servlet program.I tried to set the path for java & apache by running this batch file: ----------------------------------------------------------------- set path=%path%=;C:\Program Files\Java\jdk1.5.0\bin;C:\Program Files\Apache Group\Tomcat 4.1\bin set classpath=%classpath%=;C:\Program Files\Java\jdk1.5.0\lib;C:\Program Files\Apache Group\Tomcat 4.1\lib\tools.jar ----------------------------------------------------------------- I can execute javac command from DOS prompt,but when i compile my program javac hitCountServlet.java it cannot find javax servlet packages & hence doesnot compile. I have tried using J2EE & using corresponding batch file.It compiles & executes in J2EE
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Winners Dont Do Different Things, They Do Things Differently !!!
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Ben Souther
Sheriff
Joined: Dec 11, 2004
Posts: 13410
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You also need to add servlet-api.jar to your CLASSPATH. It's located in tomcat/common/lib. In that version of Tomcat, it may be called "servlet.jar".
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Java API J2EE API Servlet Spec JSP Spec How to ask a question... Simple Servlet Examples jsonf
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subject: creating .class file in Tomcat
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