Justin Musgrove

If you are using java 8 or guava here are a few code snippets to check if a number is within a range:

Guava
boolean containsValue = Range.open(1, 10).contains(new Integer(4));

Java 8
OptionalLong containsValue = LongStream.range(1, 10) .filter(p -> p == 4).findAny(); assertTrue(containsValue.isPresent());

"you can spend a week figuring out the perfect regex, but then a month later you " - been there done that Freed! BreakIterator deals with text boundaries, here is a solution to your use case:

String val = "Start at position 179 of the string (or at the end if it " + "isn't that long) and work backwards until you hit the " + "end of a word or a period. Chop that segment off and throw " + "it into your pot, then repeat until there's nothing left. " + "Note that the end of a word can be followed by a space, or " + "by a non-period punctuation mark like a comma, or by the " + "end of the string. Be careful not to go past the end of the " + "string in the latter case."; @Test public void test() { StringBuilder sb = new StringBuilder(); List<String> brokenStrings = new ArrayList<String>(); BreakIterator boundary = BreakIterator.getWordInstance(); boundary.setText(val); int start = boundary.first(); for (int end = boundary.next(); end != BreakIterator.DONE; start = end, end = boundary.next()) { int lengthOfNext = end - start; if ((sb.length() + lengthOfNext) > 180) { brokenStrings.add(sb.toString()); sb = new StringBuilder(); // or set to 0 } sb.append(val.substring(start, end)); // if last element if (end == val.length()) { brokenStrings.add(sb.toString()); } } for (String x : brokenStrings) { System.out.println(x); } }

Output:
Start at position 179 of the string (or at the end if it isn't that long) and work backwards until you hit the end of a word or a period. Chop that segment off and throw it into
your pot, then repeat until there's nothing left. Note that the end of a word can be followed by a space, or by a non-period punctuation mark like a comma, or by the end of the
string. Be careful not to go past the end of the string in the latter case.

I have found guava splitter is much more flexible and easier to read than regular expression. For your use case it would look like this:

List<String> elements = Splitter .on(CharMatcher.anyOf("#^")) .omitEmptyStrings() .trimResults() .splitToList( "Transmitter#MSE14_REC_FTP40 #138^TPPurgeUility_test #103^YUG_Trans #57^"); System.out.println(elements); //[Transmitter, MSE14_REC_FTP40, 138, TPPurgeUility_test, 103, YUG_Trans, 57]

Check out more guava splitter examples

Google splitter home page

Hey Jason,

We have a front end development team that started to use dust.js which is a js templating engine for prototypes and demos. It fits right into the fe dev stack/tools, close to logic less, and meshes with json well. A new project was started using java and wanted to reuse the templates that already have been developed so we needed to find a way to render those templates on the server. Writing a light piece of code we converted our java objects to json and then render the dust template in rhino.

I wrote up how you could do it using nashorn which feels like a lot of work but not all that bad.
http://www.leveluplunch.com/blog/2014/06/09/compile-load-render-dustjs-template-java-nashorn/

Hope this helps.