Hi, I am pretty confused about the following question:
How many elements will be output when the following XSL sheet is applied to the following XML document?
--------------------XSL Document-------------------------
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:element name='root'>
<xsl:call-template name="v3"/>
</xsl:element>
</xsl:template>
<xsl:template name="v3">
<xsl:variable name="v3List" select="//a[not(following::x=.)]|//x[not(preceding::a=.)] "/>
<xsl:for-each select="$v3List">
<a><xsl:value-of select="."/></a>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
--------------------XML Document-------------------------
<Root>
<B>
<a>1</a>
<a>2</a>
<a>1</a>
<x>3</x>
<x>4</x>
<x>2</x>
</B>
<B>
<a>3</a>
<a>1</a>
<a>2</a>
<a>3</a>
<x>5</x>
<x>4</x>
<x>1</x>
</B>
</Root>
The answer is 7.
First, is this a valid expression?
a[not(following::x=.)]
not() function will negate the argument, and return a boolean value, can a boolean value be put into a pair of square brackets following an element? And can anyone explain how the results come out like this. Thanks
