I am confused about the "it" that is "opening" a URL in that question.
Normally XSL is used to transform XML into HTML, as in your example. And it seems that the resulting HTML is processed by the "it" that you didn't describe. The XSL would not be doing that processing. So, what is "it"? And have you looked at the resulting HTML to see whether it looks correct?
Sorry Paul for not being clear. What I meant was, the URL in resulting HTML is not giving correct URL.
For eg., Say, www.abc.com is the value for <link> in above XML. The URL in resulting HTML page supposed to show www.abc.com but URL is shown as <a href="http://<app_server>/<app_context>/<b rel="nofollow">www.abc.com</b>" target="_blank">http://<app_server>/<app_context>/www.abc.com (relative to application context).
I am doing XML to HTML transformation by using Xalan XSLT Processor in Java.
What is the code we can use to fix the URL problem in XSL? Thanks.